Optimal. Leaf size=67 \[ \frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}-\frac{b e^2 (c+d x)^2}{6 d}+\frac{b e^2 \log \left ((c+d x)^2+1\right )}{6 d} \]
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Rubi [A] time = 0.0547487, antiderivative size = 67, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {5043, 12, 4852, 266, 43} \[ \frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}-\frac{b e^2 (c+d x)^2}{6 d}+\frac{b e^2 \log \left ((c+d x)^2+1\right )}{6 d} \]
Antiderivative was successfully verified.
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Rule 5043
Rule 12
Rule 4852
Rule 266
Rule 43
Rubi steps
\begin{align*} \int (c e+d e x)^2 \left (a+b \tan ^{-1}(c+d x)\right ) \, dx &=\frac{\operatorname{Subst}\left (\int e^2 x^2 \left (a+b \tan ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{e^2 \operatorname{Subst}\left (\int x^2 \left (a+b \tan ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}-\frac{\left (b e^2\right ) \operatorname{Subst}\left (\int \frac{x^3}{1+x^2} \, dx,x,c+d x\right )}{3 d}\\ &=\frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}-\frac{\left (b e^2\right ) \operatorname{Subst}\left (\int \frac{x}{1+x} \, dx,x,(c+d x)^2\right )}{6 d}\\ &=\frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}-\frac{\left (b e^2\right ) \operatorname{Subst}\left (\int \left (1+\frac{1}{-1-x}\right ) \, dx,x,(c+d x)^2\right )}{6 d}\\ &=-\frac{b e^2 (c+d x)^2}{6 d}+\frac{e^2 (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d}+\frac{b e^2 \log \left (1+(c+d x)^2\right )}{6 d}\\ \end{align*}
Mathematica [A] time = 0.016689, size = 54, normalized size = 0.81 \[ \frac{e^2 \left (\frac{1}{3} (c+d x)^3 \left (a+b \tan ^{-1}(c+d x)\right )-\frac{1}{6} b \left ((c+d x)^2-\log \left ((c+d x)^2+1\right )\right )\right )}{d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.037, size = 161, normalized size = 2.4 \begin{align*}{\frac{{d}^{2}{x}^{3}a{e}^{2}}{3}}+d{x}^{2}ac{e}^{2}+xa{c}^{2}{e}^{2}+{\frac{a{c}^{3}{e}^{2}}{3\,d}}+{\frac{{d}^{2}\arctan \left ( dx+c \right ){x}^{3}b{e}^{2}}{3}}+d\arctan \left ( dx+c \right ){x}^{2}bc{e}^{2}+\arctan \left ( dx+c \right ) xb{c}^{2}{e}^{2}+{\frac{b\arctan \left ( dx+c \right ){c}^{3}{e}^{2}}{3\,d}}-{\frac{d{x}^{2}b{e}^{2}}{6}}-{\frac{xbc{e}^{2}}{3}}-{\frac{b{c}^{2}{e}^{2}}{6\,d}}+{\frac{{e}^{2}b\ln \left ( 1+ \left ( dx+c \right ) ^{2} \right ) }{6\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.51354, size = 321, normalized size = 4.79 \begin{align*} \frac{1}{3} \, a d^{2} e^{2} x^{3} + a c d e^{2} x^{2} +{\left (x^{2} \arctan \left (d x + c\right ) - d{\left (\frac{x}{d^{2}} + \frac{{\left (c^{2} - 1\right )} \arctan \left (\frac{d^{2} x + c d}{d}\right )}{d^{3}} - \frac{c \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right )}{d^{3}}\right )}\right )} b c d e^{2} + \frac{1}{6} \,{\left (2 \, x^{3} \arctan \left (d x + c\right ) - d{\left (\frac{d x^{2} - 4 \, c x}{d^{3}} - \frac{2 \,{\left (c^{3} - 3 \, c\right )} \arctan \left (\frac{d^{2} x + c d}{d}\right )}{d^{4}} + \frac{{\left (3 \, c^{2} - 1\right )} \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right )}{d^{4}}\right )}\right )} b d^{2} e^{2} + a c^{2} e^{2} x + \frac{{\left (2 \,{\left (d x + c\right )} \arctan \left (d x + c\right ) - \log \left ({\left (d x + c\right )}^{2} + 1\right )\right )} b c^{2} e^{2}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.69925, size = 278, normalized size = 4.15 \begin{align*} \frac{2 \, a d^{3} e^{2} x^{3} +{\left (6 \, a c - b\right )} d^{2} e^{2} x^{2} + 2 \,{\left (3 \, a c^{2} - b c\right )} d e^{2} x + b e^{2} \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right ) + 2 \,{\left (b d^{3} e^{2} x^{3} + 3 \, b c d^{2} e^{2} x^{2} + 3 \, b c^{2} d e^{2} x + b c^{3} e^{2}\right )} \arctan \left (d x + c\right )}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.47253, size = 178, normalized size = 2.66 \begin{align*} \begin{cases} a c^{2} e^{2} x + a c d e^{2} x^{2} + \frac{a d^{2} e^{2} x^{3}}{3} + \frac{b c^{3} e^{2} \operatorname{atan}{\left (c + d x \right )}}{3 d} + b c^{2} e^{2} x \operatorname{atan}{\left (c + d x \right )} + b c d e^{2} x^{2} \operatorname{atan}{\left (c + d x \right )} - \frac{b c e^{2} x}{3} + \frac{b d^{2} e^{2} x^{3} \operatorname{atan}{\left (c + d x \right )}}{3} - \frac{b d e^{2} x^{2}}{6} + \frac{b e^{2} \log{\left (\frac{c^{2}}{d^{2}} + \frac{2 c x}{d} + x^{2} + \frac{1}{d^{2}} \right )}}{6 d} & \text{for}\: d \neq 0 \\c^{2} e^{2} x \left (a + b \operatorname{atan}{\left (c \right )}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.16889, size = 216, normalized size = 3.22 \begin{align*} \frac{2 \, b d^{3} x^{3} \arctan \left (d x + c\right ) e^{2} + 2 \, a d^{3} x^{3} e^{2} + 6 \, b c d^{2} x^{2} \arctan \left (d x + c\right ) e^{2} + 6 \, a c d^{2} x^{2} e^{2} + 6 \, b c^{2} d x \arctan \left (d x + c\right ) e^{2} - 2 \, \pi b c^{3} e^{2} \mathrm{sgn}\left (d x + c\right ) + 6 \, a c^{2} d x e^{2} - b d^{2} x^{2} e^{2} + 2 \, b c^{3} \arctan \left (d x + c\right ) e^{2} - 2 \, b c d x e^{2} + b e^{2} \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right )}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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